Question

Calculate the magnitude of the particle accelerator's magnetic field that causes an ionized helium atom (+2q e) with a momentum of 4.8X1016kgxm/s to orbit in the horizontal plane with a 1.0km radius. +2]q el = 2(1.6Xx10x10-19C) Note: q alpha A. 0.50T OB. 1.0T OC. 1.5T D. 2.0T OE. 2.5T

Answer 1

The magnetic field of the particle is 1.5 T.

(C) is correct option.

Step-by-step explanation:

Given that,

Momentum of particle
`p=4.8*10^(-16)\ kg m/s`

Radius = 1.0 km

Charge of the particle
`q=2*1.6*10^(-19)\ C`

We need to calculate the magnetic field

Using relation of radius of path in magnetic field

`r=(mv)/(qB)`

Here mv = p

`B=(p)/(qr)`

Put the value into the formula

`B=(4.8*10^(-16))/(1000*2*1.6*10^(-19))`

`B=1.5\ T`

Hence, The magnetic field of the particle is 1.5 T.