Question

Calculate the inner diameter of the steam tube between the boiler and the high pressure turbine if the average velocity of the steam(state 1) is 60 m/s.

Given is the mass flow rate at 18 kg/s.

Specific volume (v) is 0,036793 m^3/kg

Velocity (V) given as 60 m/s

How do i calculate this ??

Answer 1

The inner diameter of the steam tube is 0.1185 m.

Step-by-step explanation:

`m=\rho * A* v=(1)/(V)* A* v`

m = mass flow rate

`\rho` = density of the liquid

V=specific volume =
`(1)/(\rho )`

v = velocity of the liquid

A = area of cross-section

Diameter of the cross-section = d = 2r

Given: m = 18 kg/s, v = 60 m/s,A=?,
`V = 0.036793 m^3/kg`

`18 kg/s=(1)/(0.036793 m^3/kg)* A* 60 m/s`

`A=0.0110379 m^2`

Area of the inner cross section =
`\pi r^2=\pi (d^2)/(4)`

`\pi (d^2)/(4)=0.0110379 m^2`

d = 0.1185 m

The inner diameter of the steam tube is 0.1185 m.