Question

A physics instructor wants to produce a double-slit interference pattern large enough for her class to see. For the size of the room, she decides that the distance between successive bright fringes on the screen should be at least 3.00 cm. If the slits have a separation d=0.0175mm, what is the minimum distance from the slits to the screen when 632.8-nm light from a He-Ne laser is used?

Answer 1

0.83 m

Step-by-step explanation:

w = distance between successive bright fringes = 3.00 cm = 0.03 m

d = separation between the slits = 0.0175 mm = 0.0175 x 10⁻³ m

λ = Wavelength of the light from He-Ne laser = 632.8 x 10⁻⁹ m

D = distance of the screen from the slits = ?

Distance between successive bright fringes is given as

`w = (D\lambda )/(d)`

Inserting the values

`0.03 = (D(632.8* 10^(-9)) )/(0.0175* 10^(-3))`

D = 0.83 m