Question

Calculate the recombination rate if the excess carrier concentration is 1014cm-3 and the carrier lifetime is 1usec. (a) 108 (b) 1010 (c) 1020 (d) 1014

Answer 1

`10^(20)(cm^(-3))/(sec)`

Step-by-step explanation:

The recombination rate is denoted by R it is the ratio of excess carrier concentration and life time

The recombination rate R is given by
`R=(\Delta n)/(\tau _n)`

We have given excess carrier concentration =
`10^(14)cm^-3`

Life time
`\tau _n=10^(-6)sec`

So recombination rate
`R=(\Delta n)/(\tau _n)=(10^(14))/(10^(-6))=10^(20)(cm^(-3))/(sec)`