Answer:
a) 3.0 x 10¹⁰ J
b) 7.75 x 10³ m/s
Step-by-step explanation:
a)
ΔV = potential difference between cloud and the ground = 1.0 x 10⁹ Volts
Q = Amount of charge transferred = 30 C
ΔU = Change in energy transferred
Change in energy transferred is given as
ΔU = Q ΔV
ΔU = (30) (1.0 x 10⁹)
ΔU = 3.0 x 10¹⁰ J
b)
v₀ = initial speed of the automobile = 0 m/s
v = final speed of the automobile = ?
m = mass of automobile = 1000 kg
Using conservation of energy
ΔU = (0.5) m (v² - v₀²)
3.0 x 10¹⁰ = (0.5) (1000) (v² - 0²)
v = 7.75 x 10³ m/s