Question

Write 9^0,9^3,and 9^-2 in order from least to greatest

Answer 1

9^-2,9^0,9^3 and that is the answer

Answer 2

Correct order :
`9^(-2),9^0\text{ and }9^3`.

Explanation:

Rule: If
`a^x` and
`a^y` are two numbers and a>1, then
`a^x>a^y` for all
`x>y`.

The given numbers are

`9^0,9^3\text{ and }9^(-2)`

It these numbers base are same, i.e., 9 which is great than 1.

We know that

`-2<0<3`

Using the above rule we get

`9^(-2)<9^0<9^3`

`0.012345679<1<729`

Hence, the correct order from least to greatest is
`9^(-2),9^0\text{ and }9^3`.