Question

Calculate the amount of power (in Watts) required to move an object weighing 762 N from point A to point B within 29 seconds. Distance between point A and point B is 5.0 meters and they are at the same level. (Ignore the frictional losses)

Answer 1

0.556 Watts

Step-by-step explanation:

w = Weight of object = 762 N

s = Distance = 5 m

t = Time taken = 29 seconds

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

Equation of motion

`s=ut+(1)/(2)at^2\\\Rightarrow a=(2* (s-ut))/(t^2)\\\Rightarrow a=(2* (5-0))/(29^2)=(10)/(481)`

Mass of the body

`m=(w)/(g)=(762)/(9.81)`

Force required to move the body

`F=ma\\\Righarrow F=(762)/(9.81)* (10)/(481)`

Velocity of object

`v=u+at\\\Rightarrow v=0+(10)/(481)* 29\\\Rightarrow v=(10)/(29)`

Power

`P=Fv\\\Rightarrow P=(762)/(9.81)* (10)/(481)* (10)/(29)=0.556\ W`

∴ Amount of power required to move the object is 0.556 Watts