Answer and explanation:
In this problem, we have the following equation:
![2a+b=2a](https://img.qammunity.org/2020/formulas/mathematics/middle-school/i78s9htepz4wzzd66531f9gjwparn3trve.png)
And the problem states that
and
are nonzero real numbers. First of all, we need to assume that
and
are nonzero real numbers. Thus, let's say that:
![a=1 \\ \\ b=1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/o1gx2mgxot3j6otiwxe1b0wowaad5257in.png)
Plug in the equation, we have:
![2(1)+(1)=2(1) \\ \\ 2+1=2 \\ \\ 3=2 \ Absurd!](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1e355cs0j1hft6hnql96pu089m6ei653ju.png)
As you can see, we got an absurd statement since
. Then, the only possible solution is that
. So, we can write our equation as follows:
![2a+b=2a \\ \\ 2a+(0)=2a \\ \\ 2a=2a \ True!](https://img.qammunity.org/2020/formulas/mathematics/middle-school/numz3ixok2awokf9p48l36nzn6efushj9b.png)
Conclusion:
For any real number
, we will have that
![b=0](https://img.qammunity.org/2020/formulas/mathematics/college/5e1fepjhymrrwbi6ki0imybtobvaboljbg.png)