Answer:
A. C-1
Step-by-step explanation:
During the pentose phosphate pathway, glucose 6-phosphate is first converted into 6-phosphoglucono-lactone in the reaction catalyzed by glucose 6-phosphate dehydrogenase. The 6-phosphoglucono-lactone is then converted into 6-phospho-gluconate which in turn undergoes decarboxylation to form D-ribulose 5-phosphate and the C-1 of original glucose 6-phosphate is released in form of CO2.
Therefore, to observe the most rapid production of labeled carbon atom in form of CO2, the C-1 of glucose should be labeled.