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Glucose, labeled with 14C in different carbon atoms, is added to a crude extract of a tissue rich in enzymes of the pentose phosphate pathway. The most rapid production of 14CO2 will occur when the glucose is labeled in:

a. C-1
b. C-3
c. C-4
d. C-5
e. C-6

User Yashesh
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Answer:

A. C-1

Step-by-step explanation:

During the pentose phosphate pathway, glucose 6-phosphate is first converted into 6-phosphoglucono-lactone in the reaction catalyzed by glucose 6-phosphate dehydrogenase. The 6-phosphoglucono-lactone is then converted into 6-phospho-gluconate which in turn undergoes decarboxylation to form D-ribulose 5-phosphate and the C-1 of original glucose 6-phosphate is released in form of CO2.

Therefore, to observe the most rapid production of labeled carbon atom in form of CO2, the C-1 of glucose should be labeled.

User Kschieck
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