Question

A 0.54 cm high object is placed 8.5 cm in front of a diverging lens whose focal length is -7.5 cm. What is the height of the image?

Answer 1

`0.25` cm

Step-by-step explanation:

`h_(o)` = height of the object = 0.54 cm

`d_(o)` = distance of the object = 8.5 cm

`f` = focal length of the diverging lens = - 7.5 cm

`d_(i)` = distance of the image = ?

Using the lens equation

`(1)/(d_(o)) + (1)/(d_(i)) = (1)/(f)`

`(1)/(8.5) + (1)/(d_(i)) = (- 1)/(7.5)`

`d_(i) = - 3.98` cm

`h_(i)` = height of the image

`(h_(i))/(0.54) = (- (- 3.98))/(8.5)`

`h_(i) = 0.25` cm