Question

The pressure of an ideal gas is doubled during a process in which the energy given up as heat by the gas equals the work done on the gas. As a result, the volume is : (A) doubled (B) halved (C) unchanged

Answer 1

`V' = (V)/(2)`

So volume is halved

Step-by-step explanation:

As we know that heat energy given to the gas is equal to the work done

so as per first law of thermodynamics we know that

`\Delta Q = W + \Delta U`

now we know that

`\Delta Q = W`

so we have

`\Delta U = 0`

so we have temperature of the gas is constant

so it is an isothermal process

so here we can say

`PV = constant`

so here we can say

`P(V) = (2P)V'`

so we have

`V' = (V)/(2)`