Question

marcus ran to the park and then walked to the store. he ran 3 times as long as he walked. the total time spent walking and running was 24 minutes. what equation is used to solve for how long it took marcus to walk from the park to the store?

Answer 1

time (t) = distance (d) / speed (s)

total time (t) = time riding (t1) + time walking (t2)

1 hour = [6 miles / s1] + [1 mile / (s1 - 6 mph)]

multiply both sides by s1(s1-6)

s1(s1-6)=6(s1-6)+s1

s1^2-6s1 = 6s1-36+s1

s1^2-13s1+36=0

(s1-9)(s1-4)=0

two possible solutions s1 = 9 mph or s1 = 4 mph

since s2 = s1 - 6, then s2 = 9-6 = 3 mph (accept) or s2 = 4-6 = -2 mph (reject)

then riding speed = 9 mph and walking speed = 3 mph

Explanation:

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Answer 2

time (t) = distance (d) / speed (s)

total time (t) = time riding (t1) + time walking (t2)

1 hour = [6 miles / s1] + [1 mile / (s1 - 6 mph)]

multiply both sides by s1(s1-6)

s1(s1-6)=6(s1-6)+s1

s1^2-6s1 = 6s1-36+s1

s1^2-13s1+36=0

(s1-9)(s1-4)=0

two possible solutions s1 = 9 mph or s1 = 4 mph

since s2 = s1 - 6, then s2 = 9-6 = 3 mph (accept) or s2 = 4-6 = -2 mph (reject)

then riding speed = 9 mph and walking speed = 3 mph

Explanation: