Answer:
Pressure = 610.125 kPa
Step-by-step explanation:
Given:
Mass of the air, m = 0.3 kg
Volume of the cylinder, V = 42.9 litres = 42.9 × 10⁻³ m³
R value for the air = 287 J/kg/K
Temperature, T = 31.0° C = 304 K
Now,
we know the ideal gas equation is given as :
PV=mRT
where,
P is the pressure
on substituting the values, in the above formula
we get
P × 42.9 × 10⁻³ = 0.3 × 287 × 304
or
P = 610125.87 Pa
or
P = 610.125 kPa