Question

The solubility of a certain compound in ice-cold water is 0.16 g in 100 mL. Its solubility in hot water is 4.35 g in 100 mL. What is the best possible percent recovery we can expect for recrystallization of this compound from water?

Answer 1

96.32 %

Step-by-step explanation:

Given that:

The solubility of compound in hot water = 4.35 g / 100 mL

The solubility of compound in cold water = 0.16 g / 100 mL

Which means that in 100 mL of hot water, the dissolved compound is 4.35 g and in cold water, the dissolved compound is 0.16 g

Hence, on transition, compound that will catalyze is 4.35 - 0.16 g = 4.19 g

So,

`\%=\frac {4.19}{4.35}* 100`

Percent recovery for re-crystallization of this compound from water= 96.32 %