Question

What is the index of refraction of a material for which the wavelength of light is 0.6024 times its value in a vacuum? Identify the likely substance

Answer 1

1.66 , This value corresponds to flint glass.

Step-by-step explanation:

Refractive index is equal to velocity of the light 'c' in empty space divided by the velocity 'v' in the substance.

Or ,

n = c/v.

Also,

c = frequency × Wavelength

The formula can be written as:

n = λ / λn.

Where,

λn is the wavelength in the medium

λ is the wavelength in vaccum

Given that: λn = 0.6024 λ

So, n is:

n = λ / λn = λ / 0.6024 λ = 1.66

This value corresponds to flint glass.