Question

Find the distance CD rounded to the nearest tenth
C=(4,7) D=(7,11)

Answer 1

`{ \qquad\qquad\huge\underline{{\sf Answer}}}`

Let's use distance formula :

`\qquad \sf  \dashrightarrow \: \sqrt{(x2 - x1) {}^(2) + (y2 - y1)}`

`\qquad \sf  \dashrightarrow \: \sqrt{(7 - 4) {}^(2) + (11 - 7) {}^(2) }`

`\qquad \sf  \dashrightarrow \: \sqrt{ {3}^(2) + 4 {}^(2) }`

`\qquad \sf  \dashrightarrow \: √(9 + 16)`

`\qquad \sf  \dashrightarrow \: √(25)`

`\qquad \sf  \dashrightarrow \: 5`

So, the distance between them is 5 units ~

Answer 2

5

Explanation:

C(4, 7)

D(7, 11)

x₁ = 4; y₁ = 7

x₂ = 7; y₂ = 11

d = √[(x₂ - x₁)² + (y₂ - y₁)²]

d = √[(7 - 4)² + (11 - 7)²]

d = √(3² + 4²)

d = √(9 + 16)

d = √25

d = 5