Question

Each of the following temperature ranges is in degrees Fahrenheit. Use the formula F = 9 5 C + 32 to find the corresponding temperature range in degrees Celsius (using interval notation and assume inclusion).

A. 32 to 41 degrees
B. 77 to 86 degrees
C. -31 to -22 degrees
D. 104 to 122 degrees.

Answer 1

I would say the the answer is b

Answer 2

A. [98.6F,105.8F]

B. [170.6F,186.8F]

C. [-23.8F,-7.6F]

D. [219.2F,251.6F]

Explanation:

A. 32 to 41 degrees

`F=((9)/(5)*^(o)C)+32`

Converting 32
`^(o)C` to Farenheit:

`F=((9)/(5)*32)+32`

F=98.6F

Converting 41
`^(o)C` to Farenheit:

`F=((9)/(5)*41)+32`

F=105.8F

Writing the answer in interval notation : [98.6F,105.8F]

B. 77 to 86 degrees

`F=((9)/(5)*^(o)C)+32`

Converting 77
`^(o)C` to Farenheit:

`F=((9)/(5)*77)+32`

F=170.6F

Converting 86
`^(o)C` to Farenheit:

`F=((9)/(5)*86)+32`

F=186.8F

Writing the answer in interval notation : [170.6F,186.8F]

C. -31 to -22 degrees

`F=((9)/(5)*^(o)C)+32`

Converting -31
`^(o)C` to Farenheit:

`F=((9)/(5)*-31)+32`

F=-23.8F

Converting -22
`^(o)C` to Farenheit:

`F=((9)/(5)*-22)+32`

F=-7.6F

Writing the answer in interval notation : [-23.8F,-7.6F]

D. 104 to 122 degrees

`F=((9)/(5)*^(o)C)+32`

Converting 104
`^(o)C` to Farenheit:

`F=((9)/(5)*104)+32`

F=219.2F

Converting 122
`^(o)C` to Farenheit:

`F=((9)/(5)*122)+32`

F=251.6F

Writing the answer in interval notation : [219.2F,251.6F]