Question

Calculate the rate of heat required to bring 7.20 mol/hr of HBr gas from 43.0 degree C to 225.0 degree C at atmospheric pressure.

Answer 1

the rate of heat required is 38185,056 J/h

Step-by-step explanation:

for gases, heat is given for the expresion:

• Q ≅ mCpΔT

∴ T1 = 43°C + 273 = 316 K

∴ T2 = 225°C + 273 = 498 K

⇒ ΔT = T2 - T1 = 498 - 316 = 182 K

∴ Cp HBr (298 K) = 29.14 J / mol * K.......specific heat tables

⇒ Q = (7.2 mol/h ) * (29.14 J/mol K) * ( 182 K )

⇒ Q = 38185.056 J/h