Question

The measurement of an electron's energy requires a time interval of 1.2×10^−8 s . What is the smallest possible uncertainty in the electron's energy?

Answer 1

`1.05* 10^(-26)J`

Step-by-step explanation:

The uncertainty in energy is given by
`\Delta E=(h)/(2\pi \Delta t)`

here h is plank's constant which value is
`6.67* 10^(-34)` and
`\Delta t` is the time interval which is given as
`1.2* 10^(-8)sec`

So using all the parameters the smallest possible uncertainty in electrons energy is
`=(6.67* 10^(-34))/(2* \pi * 1.2* 10^(-8))=1.05* 10^(-26)J`