Question

Find the deBroglie wavelength of an electron with 4.0 eV.

Answer 1

Step-by-step explanation:

It is given that,

Voltage,
`V=4 eV=4* 1.6* 10^(-19)\ V= 6.4* 10^(-19)\ V`

De broglie wavelength in terms of voltage is given by :

`\lambda=(h)/(√(2meV) )`

m and e are the mass and charge on electron. So,

`\lambda=(12.27)/(√(V) )\ A`

`\lambda=\frac{12.27}{\sqrt{6.4* 10^(-19)} }\ A`

`\lambda=1.53* 10^(10)\ A`

`\lambda=1.53\ m`

So, the De broglie wavelength of an electron is 1.53 meters. Hence, this is the required solution.