Question

The nonreflective coating on a camera lens with an index of refraction of 1.29 is designed to minimize the reflection of 634-nm light. If the lens glass has an index of refraction of 1.53, what is the minimum thickness of the coating that will accomplish this task?

Answer 1

minimum thickness of the coating = 122.868 nm

Step-by-step explanation:

Given data

lens index of refraction = 1.29

wavelength = 634 nm

glass index of refraction = 1.53

to find out

minimum thickness of the coating

solution

we have given non reflective coating

so

we know that minimum thickness of the coating formula

minimum thickness of the coating = Wavelength / 4n

here n is coating index of refraction

so put here both value to get thickness

minimum thickness of the coating = Wavelength / 4n

minimum thickness of the coating = 634 / 4 ( 1.29 )

so minimum thickness of the coating = 122.868 nm