Answer:
The speed of the particle is 13767.35 m/s.
Step-by-step explanation:
given the mass m = 6.67×10^-27 kg of particle and moving with a speed v. the momentum of the particle is given by P = m×v and the planck constant h = 6.63×10^-34 m^2×kg/s. the wavelength is λ = 7.22 pm ≈7.22×10^-12 m
The de Broglie wavelength is given by:
λ = h/P
λ = h/(m×v)
v = h/λ×m
= (6.63×10^-34)/[(7.22×10^-12)×(6.67×10^-27)]
= 13767.35 m/s
Therefore, the speed of the particle is 13767.35 m/s.