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-5(t + 3)= -30
Solve for the variable!! Please

1 Answer

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Answer:


\huge\boxed{t=3}

Explanation:


-5(t+3)=-30

METHOD 1:


-5(t+3)=-30 divide both sides by (-5)


(-5\!\!\!\!\diagup(t+3))/(-5\!\!\!\!\diagup)=(-30)/(-5)


t+3=6 subtract 3 from both sides


t+3-3=6-3\\t=3

METHOD 2:


-5(t+3)=-30 use the distributive property a(b + c) = ab + ac


(-5)(t)+(-5)(3)=-30


-5t-15=-30 add 15 to both sides


-5t-15+15=-30+15


-5t=-15 divide both sides by (-5)


(-5t)/(-5)=(-15)/(-5)\\\\t=3

User Hans Vonn
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