Question

An X-ray scattering from a free electron is observed to change its wavelength by 3.14pm. At what angle to the incident direction does the scattered X-ray move?

Answer 1

angle to the incident is 107.09°

Step-by-step explanation:

Given data

wavelength = 3.14pm = 3.14 ×
`10^(-12)` m

to find out

at what angle to the incident direction scattered

solution

we know that mass of electron that is 9.11 ×
`10^(-31)` kg

and velocity of light is 3 ×
`10^(8)` m/s

and h will be 6.63 ×
`10^(-34)` J-s

so angle will be calculate by formula that is

wavelength = h ( 1- cosθ ) / (mass of electron × velocity of light )

put here all value

3.14 ×
`10^(-12)` = 6.63 ×
`10^(-34)` ( 1- cosθ) / ( 9.11 ×
`10^(-31)` × 3 ×
`10^(8)` )

cosθ = 1 - 1.294

cosθ = -0.294

θ = 107.09°

so angle to the incident is 107.09°