Answer:
the salt that has the highest solubility is
(a) AV
∴ S = 1 M
Step-by-step explanation:
a) AV ↔ A+ + V-
S S S
⇒ Ksp = [ A+ ] * [ V- ] = S * S = S²
⇒ S = √ Ksp
b) B2W ↔ 2B+ + W2-
S 2S S
⇒ Ksp = [ B+ ]² * [ W2- ] = ( 2S )² * S = 4S³
⇒ S = ∛ (Ksp / 4)
c) C2X3 ↔ 2C3+ + 3X2-
S 2S 3S
⇒ Ksp = [ C3+ ]² * [ X2- ]³ = (2S)² * (3S)³ = 4S² * 27S³ = 108S∧5
⇒ S = ( Ksp / 108 )∧(1/5)
d) DY2 ↔ D2+ + 2Y-
S S 2S
⇒ Ksp = [ D2+ ] * [ Y- ]² = S * (2S)² = 4S³
⇒ S = ∛ ( Ksp / 4 )
e) EZ3 ↔ E3+ + 3Z-
S S 3S
⇒ Ksp = [ E3+ ] * [ Z- ]³ = S * (3S)³ = 27S∧4
⇒ S = ( Ksp / 27 )∧(1/4)
assuming that Ksp = 1
a) S = √1 = 1
b) S = ∛(1/4) = 0.63
c) S = ( 1 / 108)∧(1/5) = 0.392
d) S = ∛ ( 1/4 ) = 0.63
e) S = ( 1 / 27 )∧(1/4) = 0.438