Question

Let f be an exponential function and g be a logarithmic function.

Then find
1) (f+g)(1)
2) (fg)(1)
3) (3f)(1)

Answer 1

Good evening ,

______

Answer:

1) (f+g)(1) = e

2) (fg)(1) = 0

3) (3f)(1) = 3e

___________________

Explanation:

1) (f+g)(1) = f(1) + g(1) = e¹ + log1 = e + 0 = e.

2) (fg)(1) = f(1) × g(1) = e¹ × log(1) = e¹ × 0 = e × 0 = 0.

3) (3f)(1) = 3×f(1) = 3×e¹ = 3e.

:)