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For a tubular section with outside diameter 68 mm and inside diameter 49 mm. If the tube was subjected to a torque of 1996 Nm, what would be the maximum stress in the material, fts?

User Aso Strife
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1 Answer

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Answer:


\sigma = 44.286 N/mm2

Step-by-step explanation:

given data:

outside diameter = 68 mm

inside diameter = 49 mm

torque = 1996 Nm =1996000 Nmm

we know that torque for tubular section is given as


T = (\pi)/(16) \sigma (D_0^4- D_i^4)/(D_0)

Plugging all value to get required value of maximum stress
\sigma


1996000 = (\pi)/(16) \sigma (68^4 - 49^4)/(68)


\sigma = 44.286 N/mm2

User Shashanka N
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