Question

A tensile-testing machine is to test specimens of diameter 15 mm which have ultimate tensile strengths of up to 820 N/mm2. What is the maximum tensile force the machine must be capable of?

Answer 1

14.48 N

Step-by-step explanation:

We have given the diameter of the specimens d = 15 mm ,so radius
`r=(15)/(2)=7.5 cm`

Area of the specimen
`A=\pi r^2=3.14* 0.075^2=0.01766m^2`

The maximum tensile strength = 820
`N/m^2`

We know that
`maximu\ tensile\ strength =(maximum\ tensile\ force)/(Area)`

`820=(maximu\ tensile\ force)/(0.01766)=14.48N`