Question

Find the area of ABC with vertices of A(0,2), B(8,2), and C(-4,3).

Answer 1

Check the picture below.

Answer 2

The area is 4 unit²

Explanation:

Since, the area of the triangle having vertices
`(x_1,y_1)`,
`(x_2,y_2)` and
`(x_3,y_3)` is,

`A=(1)/(2)| x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|`

Here, the vertices of the triangle ABC are,

A(0,2), B(8,2), and C(-4,3),

Hence, the area of the triangle is,

`A=(1)/(2)|0(2-2) +8(3-2)-4(2-2)|`

`=(1)/(2)|0+8-0|`

`=(8)/(2)`

`=4\text{ square unit}`