Answer: a) 0.25, b) 0.78, c) 0.71
Explanation:
Since we have given that
Number of employees in marketing = 4
Number of employees in management = 7
We need to hire committee of 3 people.
a) Find the probability that the committee has exactly 2 employees from marketing.
So, Probability becomes
![(^4C_2* ^7C_1)/(^(11)C_3)\\\\=(42)/(165)\\\\=0.25](https://img.qammunity.org/2020/formulas/mathematics/college/bj1bmhpx6a8pf44hdjxr64b7z3uqfl05f4.png)
b) Find the probability that the committee has at least one employee from marketing.
![P(x\geq 1)=1-P(x=0)\\\\P(x\geq 1)=1-(^7C_3)/(^(11)C_3)=1-0.212=0.78](https://img.qammunity.org/2020/formulas/mathematics/college/rpwn68lo323zmsahp7jkftu60aqa2n3am2.png)
c) Find the probability that the committee has at most one employee from management.
![P(x\leq 1)=P(x=0)+P(x=1)\\\\P(x\leq 1)=(^7C_3)/(^(11)C_3)+(^7C_2* ^4C_1)/(^(11)C_3)\\\\P(x\leq 1)=0.21+0.50=0.71](https://img.qammunity.org/2020/formulas/mathematics/college/om50ozmgakm0swdusc16wugrngxi6zxxpi.png)
Hence, a) 0.25, b) 0.78, c) 0.71