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Ab + cd-bd-ac = a(b-c)+d(c-b)

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Answer:

ab + cd-bd-ac = a(b-c)+d(c-b)

Explanation:

ab+cd-bd-ac

Let us first bring the like terms together

Like terms are those terms which have same variables and same exponents also. Hence in this case we do not any like terms.

Hence we will take those two terms together which has atleast one same variable

ab and ac

cd and bd

ab-ac+cd-bd

now taking a as GCF in first two terms and d as GCF in last two terms

a(b-c)+d(c-b)

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