Question

Calculate the contact angle (in deg) for the smaller of two pulleys with diameters of 500mm and 200mm. The tension ratio is 3:1 and distance between parallel shafts is 700mm

Answer 1

`\theta _A=155.25^(\circ)`

Step-by-step explanation:

Given that

`D_B=500 mm,D_A=200 mm`

Distance between pulleys= 700 mm

We have to find contact angle

In general application pulleys are connects in open configuration,So the contact angle given as follows

For small pulley

`\theta _A=\pi +2sin^(-1)(R_A-R_B)/(C)`

`\theta _A=\pi +2sin^(-1)(100-250)/(700)`

`\theta _A=155.25^(\circ)`