Answer:
The maximum torque is 388.8 N-m.
Step-by-step explanation:
Given that,
Number of turns = 150
Area = 18.0 cm
Current = 50.0 A
Magnetic field = 1.60 T
We need to calculate the maximum torque
Using formula of torque
![\tau=NIAB\sin\theta](https://img.qammunity.org/2020/formulas/physics/high-school/3d50tx08ykho5lkx47fqd4074cr8nl3ozr.png)
For maximum value of torque
![\theta=90^(\circ)](https://img.qammunity.org/2020/formulas/physics/high-school/2wy74c0p3q3r2cfh6n4dml1d5snzxckmb7.png)
Put the value into the formula
![\tau=150*50*(0.18)^2*1.60*1](https://img.qammunity.org/2020/formulas/physics/college/sbaehjxtkva8bncybp6onsq7z9by4ngy3b.png)
![\tau=388.8\ N-m](https://img.qammunity.org/2020/formulas/physics/college/yeok05z87f4k3lf9nhkz3ulr9j62u7o7im.png)
Hence, The maximum torque is 388.8 N-m.