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By heating 2 mol of nitrogen gas in a frictionless piston-cylinder, the gas expands at a constant pres- sure of 1 bar from an initial volume of 0.02 m² to a final volume of 0.05 m. The gas temperature correspondingly increases from 300 to 500 K. Assuming nitrogen is an ideal gas with a molar heat capacity CP = R (where R is the gas constant), find the amount of heat added and work derived from the gas expansion.

1 Answer

7 votes

Step-by-step explanation:

The given data is as follows.

n = 2,
V_(1) = 0.02 m^(2),
V_(2) = 0.05 m^(2)


T_(1) = 0.02 m^(2) = 300 K ,
T_(2) = 500 K

P = 1 bar

Equation for work done will be as follows.

W =
-P * \Delta V

=
-1 bar * (0.05 m^(2) - 0.02 m^(2))

= - 3000 J

Hence, formula for heat added is as follows.

Q =
nC_(p) \Delta T

Putting given values into the above formula as follows.

Q =
nC_(p) \Delta T

=
2 * (7)/(2) * (500 K - 300 K)

= 11639.6 J

Thus, we can conclude that the amount of heat added is 11639.6 J.

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