Question

A student decides they would like to have hands-on experience when it comes to transformers. The student takes an iron core (square shaped) and wraps a wire around one side 10 times and call this side the primary side (so N, - 10). The student takes another wire and wraps it around the opposite side of the iron core 20 times and calls this the secondary side (so N, -20). The student then hooks the primary side to a 1.50-V lab battery a) (10 Points) If the student then used a voltmeter to measure the voltage on the secondary side what voltage should the student measure. b) (10 Points) If the student uses an amp-meter to measure 200-mA on the secondary side how much current was entering the primary coil?

Answer 1

a ) 3 v

b ) 400 mA

Step-by-step explanation:

In case of transformer there is relation between no of turns in primary and secondary coils and voltage input and output as follows

V₁ / V₂ = n₁ / n₂

Where V₁ and V₂ are input and output voltage and n₁ and n₂ are no of turns of primary and secondary coils.

Here V₁ = 1.5 v , V₂ = ? , n₁ = 10 , n₂ = 20

Put the values in the equation above

1.5 / V₂ = 10 / 20

V₂ = 3 v.

Similarly formula for current is as follows

I₁ / I₂ = n₂ / n₁

Whereas I₁ and I₂ are current in primary and secondary coil

Put the values in the equation above

I₁ / 200 mA = 20 / 10

I₁ = 400 mA.