Answer:
a) 0.191 J
b) 0.064 C
c) 0.021 F
d) 15.5 ohm
Step-by-step explanation:
a)
P = Power produced = 0.580 W
t = time interval = 0.330 s
Energy dissipated is given as
E = P t
E = (0.580) (0.330)
E = 0.191 Joules
b)
P = Power produced = 0.580 W
V = Voltage of the source = 3 volts
i = current
Power is given as
P = i V
0.580 = i (3)
i = 0.193 A
Q = amount of charge passed
Amount of charge passed is given as
Q = i t
Q = (0.193) (0.330)
Q = 0.064 C
c)
V = Voltage of the source = 3 volts
Q = Charge passed = 0.064 C
C = Capacitance
Using the equation
Q = CV
0.064 = C (3)
C = 0.021 F
d)
V = Voltage of the source = 3 volts
i = current = 0.193 A
using ohm's law
V = i R
3 = (0.193) R
R = 15.5 ohm