Question

A 79-turn, 16.035-cm-diameter coil is at rest in a horizontal plane. A uniform magnetic field 43 degrees away from vertical increases from 0.997 T to 6.683 T in 56.691 s. Determine the emf induced in the coil.

Answer 1

The induced emf is 0.0888 V.

Step-by-step explanation:

Given that,

Number of turns = 79

Diameter = 16.035 cm

Angle = 43

Change in magnetic field
`\Delta B=(6.683-0.997)= 5.686\ T`

Time = 56.691 s

We need to calculate the induced emf

Using formula of induced emf

`\epsilon=(NA\Delta B\cos\theta)/(\Delta T)`

Where, N = number of turns

A = area

B = magnetic field

Put the value into the formula

`\epsilon=(79*\pi*(8.0175*10^(-2))^2*5.686*\cos43)/(56.691)`

`\epsilon =0.0888\ V`

Hence, The induced emf is 0.0888 V.