Answer:
Minimum diameter of the camera lens is 22.4 cm
The focal length of the camera's lens is 300cm
Step-by-step explanation:
y = Resolve distance = 0.3 m
h = Height of satellite = 100 km
λ = Wavelength = 550 nm
Angular resolution
![tan\theta\approx \theta =(y)/(h)\\\Rightarrow \theta=(0.3)/(100* 10^3)=3* 10^(-6)](https://img.qammunity.org/2020/formulas/physics/college/p00m8ffmrknvj0b3ov8piweeeg6ns2ixap.png)
From Rayleigh criteria
![sin\theta=1.22(\lambda)/(D)\\\Rightarrow D=1.22(\lambda)/(sin\theta)\\\Rightarrow D=1.22(550* 10^(-9))/(sin3* 10^(-6))=0.2236\ m=22.4\ cm](https://img.qammunity.org/2020/formulas/physics/college/8j66z61qil5h4fgxvdtwskrvvghkecgta8.png)
Minimum diameter of the camera lens is 22.4 cm
Relation between resolvable feature, focal length and angular resolution
![d=f\Delta \theta\\\Rightarrow f=(d)/(\Delta \theta)\\\Rightarrow f=(9* 10^(-6))/(3* 10^(-6))=3\ m=300\ cm](https://img.qammunity.org/2020/formulas/physics/college/jbhkc68wg3k0ygn6mn8hompqg4vxzhhigx.png)
The focal length of the camera's lens is 300cm