Question

A horse on a moving train neighed at the FO range at 493 Hz with higher harmonics. Another stationary horse on the ground heard the whinny as 1433 Hz in the GO range. Find the train moving direction, going away from or coming nearer to the stationary horse? Find the train speed. Give reasons 443W2 an bns 6mite

Answer 1

Step-by-step explanation:

It is given that,

Frequency of the object,
`f_o=493\ Hz`

Frequency of another object, f = 1433 Hz

Let
`v_s=340\ m/s` is the speed of sound and v is the speed of the train. The speed of the train can be calculated using Doppler's effect as :

`f=(v_s)/(v_s-v)* f_o`

`v=v_s-(f_ov_s)/(f)`

`v=340-(493* 340)/(1433)`

v = 223.02 m/s

So, the speed of the train is 223.02 m/s. Hence, this is the required solution.