Answer:
![u=-6 \\ \\ v=-6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/eef8f3xuf3gaw5kae27n7qqbrjwwopwuzj.png)
Explanation:
In this exercise, we have two equations, namely:
![u=v \ and \ 6u=2v-24](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ma9zpx4kmhsadi4xaceezy5eeun1qmjqo1.png)
And we are asked to solve this problem by graphing. In this way, we can write a system of linear equations in two variables, but first of all, let's rewrite:
![u=y \\ \\ v=x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/c5tnpeksgx4pq9idffuwofazteym03we94.png)
Then:
![\left\{ \begin{array}{c}y=x\\6y=2x-24\end{array}\right.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8gffmyjgedpjgxetwmloty8bh4b3le7poc.png)
So here we have two lines.
The first one is:
![\boxed{y=x}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vegyxt51kqm39mi3k4om4tjb2l1n0tlrc2.png)
This line passes through the origin and has a slope
![m=1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rtiyn2ma3t4wtadhm2zmr58y76wm2n2t8n.png)
The second one is:
![6y=2x-24 \\ \\ \therefore y=(2x-24)/(6) \\ \\ \therefore \boxed{y=(1)/(3)x-4}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/184gdkkxek4nhujygyxb2ou0fxyp00x88g.png)
This line has a slope
and cuts the y-axis at
![b=-4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5mgx0n0itkxq15k0vgh8gewe86906w8j1y.png)
By using graph tools, we get the graph shown below, then:
![x=-6 \\ \\ y=-6 \\ \\ \\ Since \ u=y \ and \ v=x, then: \\ \\ u=-6 \\ \\ v=-6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6ddzuez0ieaw62i2pomuvrd3cz4tx9lf83.png)