Question

Calculate the radiation dosage (in grays) for an 79-kg person that is exposed for 6.0 seconds to a 3.0 C source of beta radiation. Assume that 100% of the radiation is absorbed and each beta particle has an energy of 1.6 10-13 J

Answer 1

The absorbed energy by the person is
`6.74*10^(-4)\ grays`

Step-by-step explanation:

Given that,

Mass of person = 79 kg

Time = 6.0 s

Beta radiation = 3.0 C

Energy
`E = 1,6*10^(-13)\ J`

We need to calculate the number of disintegration in 3 ci

`N=3.0*(3.7*10^(10)\ disintegration/s)/(ci)*3.0\ s`

`N=3.33*10^(11)\ disintegration`

We need to calculate the total energy of beta particle

`E=3.33*10^(11)*1.6*10^(-13)\ J`

`E=0.05328\ J`

We need to calculate the energy absorbed by the 79 kg of person

`E'=(E)/(m)`

Put the value into the formula

`E'=(0.05328)/(79)`

`E'=6.74*10^(-4)\ J/kg = grays`

Hence, The absorbed energy by the person is
`6.74*10^(-4)\ grays`