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What is the magnetic field inside a coil with the following conditions: 228 number of turns, 0.952 A of current and a length of 2.29 cms.

User Sriram R
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1 Answer

1 vote

Answer:

The magnetic field inside a coil is 0.0119 T.

Step-by-step explanation:

Given that,

Number of turns = 228

Current = 0.952 A

Length = 2.29 cm

We need to calculate the magnetic field

Using formula of magnetic field


B=(\mu_(0)NI)/(l)

Where, B = magnetic field

l = length

I = current

N = number of turns

Put the value into the formula


B=(4\pi*10^(-7)*228*0.952)/(2.29*10^(-2))


B=0.0119\ T

Hence, The magnetic field inside a coil is 0.0119 T.

User Dsomnus
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8.3k points