Question

What is the energy range (in eV) of photons of wavelength 410 nm to 750 nm ? Express your answers using two significant figures separated by a comma.

Answer 1

Step-by-step explanation:

It is given that,

Wavelength 1,
`\lambda_1=410\ nm=410* 10^(-9)\ m`

Wavelength 2,
`\lambda_2=750\ nm=750* 10^(-9)\ m`

Energy of a photon having wavelength 1 is given by :

`E=(hc)/(\lambda)`

`E_1=(6.62* 10^(-34)* 3* 10^8)/(410* 10^(-9))`

`E_1=4.84* 10^(-19)\ J`

Energy of a photon having wavelength 2 is given by :

`E=(hc)/(\lambda)`

`E_2=(6.62* 10^(-34)* 3* 10^8)/(750* 10^(-9))`

`E_2=2.64* 10^(-19)\ J`

Hence, this is the required solution.