Question

Determine the equation of motion of a point mass m attached to a coiled spring with spring constant k, initially displaced a distance x, from equilibrium, and released with velocity V, subject to no damping or other external forces. 1. m= 10kg , k = 1000/m, x, = 1m., V, = 0

Answer 1

Step-by-step explanation:

Angular velocity w =
`\sqrt{(m)/(k) }`

m = 10 ; k = 1000N / m

Putting these values we get

w = 0.1

Amplitude A = 1 m

So equation of S H M is

x = A cos ( wt )

Velocity dx / dt = Aw sin wt when t = 0 , velocity = 0 (given )

The equation for motion is

x = 1 x cos ( 0.1 t )