Question

Compute the permutation. 3 P 1

Answer 1

3

Explanation:

Using the definition

n
`P_(r)` =
`(n!)/((n-r)!)`

where n! = n(n - 1)(n - 2)........ × 3 × 2 × 1

Hence

3
`P_(1)`

=
`(3!)/(2!)`

=
`(3(2)(1))/(2(1))` =
`(6)/(2)` = 3