A wave is sent along the first rope transmitting a power of 57.3 W. It has a wavelength of 5.54 cm and velocity of 13.87 m/s The linear density of the rope is 567 g/m. What is t…

Question

asked Jan 3, 2020 201k views

1 Answer

MokiTa · Answer 1 · 2020-01-09T09:50:49+0000

Answer:

A = 2.43*10^(-3) m

Step-by-step explanation:

power through string can be determined as shown in figure

$P  = 2\pi ^2 HVA^2F^2$

Where

P = 57.3 W

V = 13.87 m/s

H = 567 g/m

we know that

$V = f *\lambda$
$\lambda = (v)/(f)$

therefore
$P  = 2\pi ^2 HVA^2((v)/(f))^2$

$57.3 = (2\pi ^2 * 0.567 *13.87^(3)* A^2)/((5.54*10^(-2))^2)$

A = 2.43*10^(-3) m