Question

A wave is sent along the first rope transmitting a power of 57.3 W. It has a wavelength of 5.54 cm and velocity of 13.87 m/s The linear density of the rope is 567 g/m. What is the amplitude of the wave? A1 =

Answer 1

`A = 2.43*10^(-3) m`

Step-by-step explanation:

power through string can be determined as shown in figure

`P  = 2\pi ^2 HVA^2F^2`

Where

P = 57.3 W

V = 13.87 m/s

H = 567 g/m

we know that

`V = f *\lambda`
`\lambda = (v)/(f)`

therefore
`P  = 2\pi ^2 HVA^2((v)/(f))^2`

`57.3 = (2\pi ^2 * 0.567 *13.87^(3)* A^2)/((5.54*10^(-2))^2)`

`A = 2.43*10^(-3) m`