Question

A 20.0 F capacitor initially charged to 30.0 uC is discharged through a 3.00 k resistor. How long does it take to reduce the capacitor's charge to 15.0 C? Express your answer with the appropriate units. ?

Answer 1

t = 0.04159 s

Step-by-step explanation:

when a capacitor and resister are connected in series. charge on its plates decreases exponentially

`q = qo * e^{(-t)/(RC)}`

where,

CHARGE q =15.0 C

INITIAL CHARGE q_0 = 30.0 uc

Resistor R = 20.0 F

capacitor C = 3.00

`15 = 30* e^{(- t)/((20* 10^(-6) * 3* 1000))`

t = 0.04159 s