Question

Light is incident on the left face of an isosceles prism; with an apex angle of 49o, such that the light exiting the right face is parallel to its surface.

What is the index of refraction of the prism, if the angle of incidence on the left face side is 19o to the normal of the face? Light is incident towards the apex.

Answer 1

Step-by-step explanation:

Cool

Answer 2

`\mu = 1.645`

Step-by-step explanation:

By Snell's law we know at the left surface

`\theta_i = 19^o`

`\theta_r = ?`

`\mu_1 = 1`

`\mu_2 = \mu`

now we have

`1 sin19 = \mu sin\theta_r`

`0.33 = \mu sin\theta_r`

now on the other surface we know that

angle of incidence =
`\theta_r'`

`\theta_e = 90`

so again we have

`\mu sin\theta_r' = 1 sin90`

so we have

`\theta_r = sin^(-1)(0.33)/(\mu)`

`\theta_r' = sin^(-1)(1)/(\mu)`

also we know that

`\theta_r + \theta_r' = 49`

`sin^(-1)(0.33)/(\mu) + sin^(-1)(1)/(\mu) = 49`

By solving above equation we have

`\mu = 1.645`