Question

While rearranging a dorm room, a student does 310 J of work in moving a desk 2.9 m. What was the magnitude of the applied horizontal force?

Answer 1

The horizontal force is 106.89 N.

Step-by-step explanation:

Given that,

Work done = 310 J

Distance = 2.9 m

We need to calculate the horizontal force

Using formula of work done

`W= Fd\cos\theta`

Where,
`\theta=0^(\circ)`

`W=F\cdot d`

Put the value into the formula

`310=F\cdot 2.9`

`F=(310)/(2.9)`

`F=106.89\ N`

Hence, The horizontal force is 106.89 N.