Answer:
0.020 Kg/s
Step-by-step explanation:
Given:
Volume of the rigid tank, V = 21.225 m³
Initial density of the air, ρ₁ = 1.829 Kg/m³
Final density of the air, ρ₂ = 5.007 Kg/m³
Total time for the procedure, t = 56.101 minutes = 56.101 × 60 = 3366.06 s
Now,
Mass = Density × volume
thus,
Initial mass of the air in the tank = ρ₁ × V = 1.829 × 21.225 = 38.820 Kg
Final mass of the air in the tank = ρ₂ × V = 5.007 × 21.225 = 106.273 kg
Therefore,
Total mass inflow in the tank = Final mass of the air - Initial mass of the air
or
Total mass inflow in the tank = 106.273 - 38.820 = 67.453 Kg
hence,
the mass flow rate = Mass inflow / Time
or
The mass flow rate = 67.453 Kg / 3366.06 s = 0.020 Kg/s